³log5.√5log9.8log2 —————————— = ²log8-²log2 A. 4/6 B. 7/6 C. 5/3 D. 13/6 E. 26/6

semoga membantu yaa :)

Logaritma.

[tex]\displaystyle \frac{^3\log 5~^{\sqrt{5}}\log 9~^8\log 2}{^2\log 8-^2\log 2}\\ =\frac{^3\log 5\times ^{5^{1/2}}\log 3^2\times ^{2^3}\log 2}{3-1}\\ =\frac{^3\log 5\times \frac{2}{1/2}^5\log 3\times \frac{1}{3} ^2\log 2}{2}\\=\frac{\frac{4}{3}}{2}=\frac{4}{6}=\frac{2}{3}[/tex]
Jawaban: A.