1. Jika 2log3=a, 5log2=b, maka 15log12 adalah.... 2.Jika 5log3=p, maka 15log81=... sama cara kerjanya yaaaaa tolong

LogAritMa

1][
2'log 3 = a
5'log 2 = b

15'log 12
= 2'log 12 / 2'log 15
= 2'log (2² × 3) / 2'log (3 × 5)
= (2 . 2'log 2 + 2'log 3) / (2'log 3 + 2'log 5)
= (2 + a) / (a + 1/b)
= b(2 + a) / (ab + 1)

2][
5'log 3 = p

15'log 81
= 3'log 81 / 3'log 15
= 3'log 3⁴ / (3'log 3 + 3'log 5)
= 4 / (1 + 1/p)
= 4p / (p + 1)

1.Jika 2log3=a, 5log2=b,
maka 15log12 =(log 12 ) /( log15)
=(log 2x2x3)/(log 5x3)
=(2× 2log2+2log3) / (2log5+2log3)
=(2×1+a) / ( 1/b+a)
(2+a) x( ab/(1+ab))



2.Jika 5log3=p, maka 15log81=...
Log81/log 15 =
Log 3x3x3x3)/(log 5x3)
4x(3Log 3)/(3log 5+3log3)
4 / (1/p+1)