no. 3a bantu, please, butuh banget

2²×⁻¹ - 9. 2×⁻² + 1 = 0
2²×/2 - 9 . 2×/4 + 1 = 0 (kedua ruas dikali 4)
2. 2²× - 9. 2× + 4 = 0
misal 2× = a
2a² - 9a + 4 = 0
(2a - 1)(a - 4)= 0
a = 1/2 dan a = 4
2× = 2⁻¹ dan 2× = 2²
x = -1 dan x = 2

jumlah x = -1 + 2 = 1