berapa gr mgcl2 (mg= 24 cl= 35,5) yg harus dilarutkan sedalam 100 gr air agar larutan tersebut mendidih pd suhu 103,2 °C (kb air =0,52) bantu yaa

Mr = 95 gram/mol
wp = 100 gram
Tb = 103,2°C
Kb = 0,52°C
wt = .........................?

ΔTb = Tb - Tb°
       = 103,2 - 100
       = 3,2°C

ΔTb = m.Kb
ΔTb = wt/Mr x 1000/wp x Kb
3,2   = wt/95 x 1000/100 x 0,52
3,2   = wt/95 x 5,2
wt    = (3,2 x 95)/5,2
wt    = 58,46 gram