Matematika

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hasil Integral (6x²+4x)√(x³+x²-7) dx=hasil Integral (6x²+4x)√(x³+x²-7) dx=

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  • misalin
    u=x^3+x^2-7
    du=3x^2+2x dx
    2du=6x^2+4x dx

    integral(6x^2+4x)√(x^3+x^2-7) dx
    =integral 2u^(1/2) du
    =4/3 u^(3/2)+c
    =4/3 (x^3+x^2+7)^(3/2) + c

    ^ dibaca pangkat

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