hasil Integral (6x²+4x)√(x³+x²-7) dx=
Matematika
kahendred
Pertanyaan
hasil Integral (6x²+4x)√(x³+x²-7) dx=
1 Jawaban
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1. Jawaban Anonyme
InTegraL
Misal :
u = x³ + x² - 7
du/dx = 3x² + 2x
du = (3x² + 2x) dx
2 du = 2(3x² + 2x) dx
2 du = (6x² + 4x) dx
∫(6x² + 4x)√(x³ + 2x - 7) dx
= ∫u^1/2 . 2du
= 2 ∫u^1/2 du
= 2/(3/2) u^3/2 + C
= 4/3 u√u + C
= 4/3 (x³ + x² - 7)√(x³ + x² - 7) + C