soal lihat gambar ya , palai cara tolong secepatnya

Logaritma.

Nomor 18
[tex]\displaystyle \frac{\log_{27}9+\log_2 3~\log_{\sqrt{3}}4 }{\log_3 2-\log_3 18}\\ =\frac{\log_{3^3}3^2+\log_2 3~\log_{3^{1/2}}2^2}{\log_3 2-\log_3 (9\times 2)}\\ =\frac{\frac{2}{3}\log_3 3+\log_2 3~\frac{2}{1/2}\log_3 2}{\log_3 2-(\log_3 9+\log_3 2)}\\ =\frac{\frac{2}{3}(1)+4(1)}{-2}\\ =-\frac{14}{6}=-\frac{7}{3}[/tex]
Jawaban: D.

Nomor 19
[tex]\displaystyle a^b=c\rightarrow ^a\log c=b\\ \left ( \frac{a^p}{b^q} \right )=c^{p-q}\rightarrow \left ( \frac{b^q}{a^p} \right )=c^{q-p}=c^{-(p-q)}\\ \log \frac{a^2}{b^2}=12\\ \left ( \frac{a}{b} \right )^2 =10^{12}\\ \frac{b}{a}=10^{-6}\\ \sqrt[3]{\frac{b}{a}}=\sqrt[3]{10^{-6}}=10^{-2}\\ \log \sqrt[3]{\frac{b}{a}}=-2[/tex]
Jawaban: A.