jika di ketahui 3log5 = m dan 2log5 = n maka 35log15 = (tolong ya + penjelasanya)

35'log 15 = (5'log 15) / (5'log 35)
= (5'log 3 + 5'log 5) / (5'log 7 + 5'log 5)
= (1/m + 1) / (1/n + 1)
= ((1 + m)/m) / ((1 + n)/n
= (n + nm) / (m + mn)

[tex] \frac{5log7 + 1}{1/m + 1} [/tex]