integral (x - 1) sin x dx

integral (x-1) sin x dx = ...

u=x-1
du=dx

dv=sin x dx
v= integral sin x dx
v= - cos x

integral u dv = u.v - integral v du
= -(x-1)cos x - integral (-cos x) dx
= -(x-1)cos x + sin x + c

nyoba cara lain 

∫ (x - 1) sin x dx
= ∫ x sin x dx - ∫ sin x dx
= (x)(-cos x) - (1)(-sin x) - (-cos x) + c
= - x cos x + sin x + cos x + c
= (-x +1) cos x + sin x + c
= -(x - 1) cos x + sin x + c
...