Matematika

Pertanyaan




Bentuk sederhana dari
(3a6b5/81a9b²)-¹ =


A. (3a/b) ³ =
B. (3b/a) ³ =
C. (a/3b) ³ =
D. (b/3a)³ =
E. (3ab) ³ =

Tlg cepat iya kak

1 Jawaban

  • = {(3/81).b^(5-2) / a^(9-6)}^-1
    = {(1/27) . b^3 / a^3}^-1
    = {(1/3³) . b^3 / a^3}^-1
    = (b^3 / 3^3.a^3}^-1
    = 3^3 . a^3 / b^3
    = (3a/b)³

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