{(2x+3) (5x²+15x-1)⁴ dx

Integral

= int (2x + 3)(5x² + 15x - 1)⁴ dx
u = 5x² + 15x - 1

du = 10x + 15 dx
1/5 du = 2x + 3 dx

= int u⁴ . (1/5)du
= 1/5 int u⁴ du
= 1/5 : (4+1) u^(4+1) + c
= (1/25) u^5 + c
= (1/25) (5x² + 15x - 1)^5 + c

semoga berguna +_+