kenaikan titik didih larutankno3 0,75 molal adalah...(kb air=0,52;arn=14,0=16

▲Tb= (gr ter/ mr × 1000/ gr pel) × kb × i
= m×kb×i
= 0.75× 0.52× 2
= 0.78 ------ kenaikan titik didih
Tb = Tb pel + Tb lar
= 100 + 0.78
= 100.78°C ------ titik didih larutan