tentukan fraksimol dari larutan glukosa 2 molal ( mr glukosa 180, mr air 18 )
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tentukan fraksimol dari larutan glukosa 2 molal ( mr glukosa 180, mr air 18 )
1 Jawaban
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1. Jawaban gugumgumilar7
molalitas glukosa = 2
[massa glukosa/Mr] x [1000/massa air]
= 2
[g/180] x [1000/p] = 2
g = 0,36p
fraksi mol zat terlarut glukosa
Xt = mol glukosa/ [mol glukosa + mol air]
Xt = [g/180] / [(g/180) + (p/18)]
Xt = g / [g + 10p]
Xt = 0,36p / [0,36p + 10p]
Xt = 36 / [36 + 1000]
Xt = 36/1036 = 9/259