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Pertanyaan

tentukan fraksimol dari larutan glukosa 2 molal ( mr glukosa 180, mr air 18 )

1 Jawaban

  • molalitas glukosa = 2
    [massa glukosa/Mr] x [1000/massa air]
    = 2
    [g/180] x [1000/p] = 2

    g = 0,36p

    fraksi mol zat terlarut glukosa
    Xt = mol glukosa/ [mol glukosa + mol air]
    Xt = [g/180] / [(g/180) + (p/18)]
    Xt = g / [g + 10p]
    Xt = 0,36p / [0,36p + 10p]
    Xt = 36 / [36 + 1000]
    Xt = 36/1036 = 9/259

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