Matematika

Pertanyaan

integral batas atas 2 batas bawah 0 2x+4 diper (x kuadrat+4x-1) kuadrat dx

1 Jawaban

  • InTegraL

    Misal :
    u = x² + 4x - 1
    du = (2x + 4) dx

    ∫(2x + 4)/(x² + 4x - 1)² dx [2...0]
    = ∫u^-2 du
    = 1/-1 . u^-1
    = -1/(x² + 4x - 1)
    = (-1/(2² + 4.2 - 1)) - (-1/(0 + 0 - 1))
    = -1/11 - 1
    = -12/11

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