integral batas atas 4 dan batas bawah 1 (√x-3)³/√x dx
Matematika
arip56
Pertanyaan
integral batas atas 4 dan batas bawah 1 (√x-3)³/√x dx
1 Jawaban
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1. Jawaban Anonyme
InTegraL
Misal :
u = √x - 3 --> du = 1/2 x^-1/2 dx
x^-1/2 dx = 2 du
1/√x dx = 2 du
∫((√x - 3)³ /√x ) dx [4...1]
= ∫u³ . 2 du
= 2 ∫u³ du
= 2/4 u⁴
= 1/2 (4⁴ - 1⁴)
= 1/2 (256 - 1)
= 255/2
= 127,5 satuan luas