pemfaktoran dari x^2 + 2x-25=0 4x^2 -20x +24=0 12x^2 + 28x - 5 =0
Matematika
Leorhessa07
Pertanyaan
pemfaktoran dari
x^2 + 2x-25=0
4x^2 -20x +24=0
12x^2 + 28x - 5 =0
x^2 + 2x-25=0
4x^2 -20x +24=0
12x^2 + 28x - 5 =0
1 Jawaban
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1. Jawaban Anonyme
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4x² - 20x + 24 = 0
x² - 5x + 6 = 0
(x - 2)(x - 3) = 0
x = 2 atau x = 3
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12x² + 28x - 5 = 0
(6x - 1)(2x + 5) = 0
x = 1/6 atau x = -5/2
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x² + 2x - 25 = 0
x1.2 = (-b ± √(b² - 4ac))/2a
x1.2 = (-2 ± √(2² - 4.1.(-25)))/2.1
x1.2 = (-2 ± √104)/2
x1.2 = (-1 ± √26)
x1 = -1 + √26
x2 = -1 - √26
x² + 2x - 25 = 0
(x - (-1 + √26))(x - (-1 - √26)) = 0
(x + 1 - √26)(x + 1 + √26) = 0