Matematika

Pertanyaan

½ log 9 x ⅓ log 7 x 49 log 32

1 Jawaban

  • (1/2)'log 9 . (1/3)'log 7 . 49'log 32
    = (2^-1)'log 3^2 . (3^-1)'log 7 . (7^2)'log 2^5
    = (2/-1)(1/-1)(5/2) . 2'log 3 . 3'log 7 . 7'log 2
    = (-2 × -1 × 5/2) . 2'log 2
    = 5 . 1
    = 5

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