sederhanakanlah! a.x2 +2x /x2 -4 b.x2 -x -2 /x2 -1 c.2x2 -x -10 /x2 -x -6 pakai cara!!

[tex]$\begin{align}a.)~~~~ \frac{x^2 + 2x}{x^2 - 4} &= \frac{x(x + 2)}{(x + 2)(x - 2)} \\ &= \frac{x}{x - 2} \end{align}[/tex]

[tex]$\begin{align}b.)~~~~ \frac{x^2 - x - 2}{x^2 - 1} &= \frac{(x + 1)(x - 2)}{(x + 1)(x - 1)} \\&= \frac{x - 2}{x - 1} \end{align}[/tex]

[tex]$\begin{align}c.)~~~~ \frac{2x^2 - x - 10}{x^2 - x - 6} &= \frac{(2x - 5)(x + 2)}{(x - 3)(x + 2)} \\ &= \frac{2x - 5}{x - 3} \end{align}[/tex]